As we know,
S = ut + 1/2at2
Given,
u = 0 m s -1
S = 270 m
t = 3 s
Substituting the values in the formula above we get,
270 = 0 × 3 + 1/2 × a × 32
or, 270 = a × 9/2
or, 9a = 270 × 2
or, 9a = 540
or, a = 540/9 = 60 m s-2
To find out velocity after t = 10 s.
v = u + at
Substituting the values in the formula above we get,
v = 0 + (60 × 10) = 600 ms-1
Hence, velocity after 10 s = 600 m s-1