According to equation of motion —
S = ut + 1/2 at²
Where,
distance covered = S
initial velocity u = 0
acceleration a = 2 m s-2
time t = 2 s
Substituting the values in the formula for u = 0, we get,
S = 0 × 2 + 1/2 × 2 × 2²
= 0 + 4 = 4 m
Hence, distance covered = 4 m