(i) We know that work done is a product of force and displacement
W = F x S = mgh
Given,
m1 = 40 kgf
m2 = 30 kgf
t1 = 4 min = 4 × 60 =240 sec
t2 = 3 min = 3 × 60 = 180 sec
h1 = h2 = 30 × 20 = 600 cm = 6 m
(i) Workboy : Workgirl = m1gh1 : m2gh2
= m1 : m2
= 4 : 3
Therefore,
Work done by boy : Work done by girl = 4 : 3
(ii) The power developed —
We know that,
Power = work\over Time
Powerboy : Powergirl = 40 × 10 × 6\over 240 : 30 × 10 × 6\over 180
= 2400\over 240 : 1800\over 180
= 10 : 10 = 1 : 1
Power developed by boy : Power developed by girl = 1:1.
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).