(π’) Time of ascent = 3s
Initial velocity = u
Final velocity, v = 0 m/s
Acceleration, a = g = – 9.8 m/s2
β΄Β Β Β Β Β Β Β Β Β Β Β v = u+ at
βΉΒ Β Β Β Β Β Β Β Β Β 0 = u + (- 9.8) x 3
βΉΒ Β Β Β Β Β Β Β Β Β 0 = u – 29.4
β΄Β Β Β Β Β Β Β Β Β Β Β u = 29.4 m/s
β΄ Maximum height of the stone reached = {v^2 - u^2 \over 2a}Β Β Β Β Β Β [β΅ π£ 2 β π’ 2 = 2as]
= {(0)^2β (29.4)^2 \over 2 \times (β9.8)} = {β864.4 \over -19.6} = 44.1 m
(ii) The bird was hit after a second while returning.
β΄ Initial velocity, u = 0 m/s
Distance travelled = s
Time taken = 1 s
Acceleration, a = g = 9.8 m/s2
s = π’π‘ + {1\over2} gt2
= 0 x 1 + {1\over2} x 9.8 x (1)2Β m = 0 + ({1\over2} x 9.8) = 4.9 m
The height of the bird from the ground = 44.1 m – 4.9 m = 39.2 m
(π’π’π’) Each and every living organism is a part and parcel of our life, because living organisms maintain biodiversity on earth. Therefore, we should treat the living beings in a polite way. This value is not shown by the boy as he hits the bird.
Observe the graph and answer the following questions. Assume that g = 10 m/s2 and that there is no air resistance. (a) In which direction is the ball moving at point C? (b) At which point is the ball stationary? (c) At which point is the ball at its maximum height? (d) what is the ball’s acceleration at point C? (e) What is the ball’s acceleration at point A? (f) What is the ball’s acceleration at point B? (g) At which point does the ball have the same speed as when it was thrown?