I = 1.5 A
Potential difference = 6 V
R = ?
From Ohm’s Law,
V = IR
Substituting the values in the formula, we get,
6 = 1.5 × R
⇒ R = 6 / 1.5 = 4 Ω
Hence, the resistance of filament of bulb while glowing = 4 Ω
I = 1.5 A
Potential difference = 6 V
R = ?
From Ohm’s Law,
V = IR
Substituting the values in the formula, we get,
6 = 1.5 × R
⇒ R = 6 / 1.5 = 4 Ω
Hence, the resistance of filament of bulb while glowing = 4 Ω
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