I = 1.5 A

Potential difference = 6 V

R = ?

From Ohm’s Law,

V = IR

Substituting the values in the formula, we get,

6 = 1.5 × R

⇒ R = 6 / 1.5 = 4 Ω

Hence, the resistance of filament of bulb while glowing = 4 Ω

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## Question

# A bulb draws current 1.5 A at 6.0 V. Find the resistance of filament of bulb while glowing.

## Answer

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I = 1.5 A

Potential difference = 6 V

R = ?

From Ohm’s Law,

V = IR

Substituting the values in the formula, we get,

6 = 1.5 × R

⇒ R = 6 / 1.5 = 4 Ω

Hence, the resistance of filament of bulb while glowing = 4 Ω

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