Here, š¢ = 80 šš/ā = {80 \times 1000\over3600} ms^{-1}={200\over9}ms^{-1}
v = 60 km/h =Ā {60 \times 1000\over3600} ms^{-1}={150\over9}ms^{-1}
š” = 5 š
Therefore, acceleration, a = ?
We know that, v = u + at
ā a = {{v-u} \over t} = {({{150\over9} - {200\over9}})\over5}= {- {50\over9}\over5}=-{10\over9}=-1.1ms^{-2}
Therefore, Acceleration is -1.1 ms -2 .