Here, ๐ข = 80 ๐๐/โ = {80 \times 1000\over3600} ms^{-1}={200\over9}ms^{-1}
v = 60 km/h =ย {60 \times 1000\over3600} ms^{-1}={150\over9}ms^{-1}
๐ก = 5 ๐
Therefore, acceleration, a = ?
We know that, v = u + at
โ a = {{v-u} \over t} = {({{150\over9} - {200\over9}})\over5}= {- {50\over9}\over5}=-{10\over9}=-1.1ms^{-2}
Therefore, Acceleration is -1.1 ms -2 .