(i) As we know,
Distance = Speed x time
Initial velocity = u = 25 m s-1
Final velocity = 0
time = 5 s
Substituting the values in the formula above we get,
Distance = 25 × 5 = 125 m
Hence, distance covered = 125 m.
(ii) Retardation (-a) = u-v\over t
t = 10 s
Substituting the values in the formula above we get,
Retardation (-a) = – 0-25\over 10 = 2.5 m s-2
Hence, retardation of the car = 2.5 m s-2
(iii) As we know,
v2 – u2 = 2aS
Substituting the values in the formula above we get,
02 – 252 = 2 × (-2.5) × S
or, -625 = – 5 S
or, S = -625\over -5
or, S = 125 m
Hence, the distance travelled by the car after applying the brakes = 125 m.