Mass = 50 kg
h1 = 0 m
h2 = 15 m
(i) Work done by man = mgh2
Substituting the values we get,
W = 50 × 9.8 × 15 = 7350 J
(ii) Increase in his potential energy = Mg (h2 – h1)
= 50 × 9.8 × (15 – 0)
= 7350 J
Mass = 50 kg
h1 = 0 m
h2 = 15 m
(i) Work done by man = mgh2
Substituting the values we get,
W = 50 × 9.8 × 15 = 7350 J
(ii) Increase in his potential energy = Mg (h2 – h1)
= 50 × 9.8 × (15 – 0)
= 7350 J
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).