(a) (i) Work done = force x displacement
Hence, work done is same for both men as both carry 50 kg weight to a height of 2m.
Therefore,
Work done by first man : Work done by second man = 1 : 1
(ii) Let the work done by both men be W.
Power = work\over time
Power developed by Man A : Power developed by Man B = W\over 20 : W\over 50
= 5\over 2
Power developed by Man A : Power developed by Man B = 5:2
(b)
(i) As we know,
W = F × S = mgh
W = 50 × 10 × 2 = 1000 J
(ii) Power developed by Man A (PA) = 1000\over 20
= 50 W
Power developed by Man B (PB) = 1000\over 50
= 20 W
(a) Calculate the change in the gravitational potential energy of the skier between A and B. (b) If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.(Take g = 10 ms-2).