Question

A particle starts to move in a straight line from a point with a velocity 10 ms-1 and acceleration -2.0 ms-2. Its position at t = 5 s will be : (i) 5 m (ii) 10 m (iii) 20 m (iv) 25 m

February 27, 2024

Answer

25 m

Reason – Given,

u = 10 ms^-1; a = -2.0 ms^-2; t = 5 s

Using, S = ut + 1/2 at²

S = (10 × 5) + 1/2 × (-2) × 5² = (50 – 25) = 25 m

Hence, its position at t = 5 s will be 25 m

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