Question

A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at step.)
NH4NO3 ⟶ N2O + 2H2O
(i) What volume of di nitrogen oxide is produced at the same time as 8.96 litres of steam.
(ii) What mass of ammonium nitrate should be heated to produce 8.96 litres of steam [Relative molecular mass of NH4NO3 is 80]

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Answer

NH4NO3 ⟶ N2O + 2H2O

80 g           1 vol    2 vol

1 vol. of di nitrogen produced at the same time as 8.96 litres of steam (2 vol)

Hence, Vol of di nitrogen = 8.96\over2

= 4.48 lit.

Hence, the volume of di nitrogen oxide produced = 4.48 lit.

(ii) 2 vol = (2 x 22.4) lit steam is produced from 80 g NH4NO3

∴ 8.96 lit of steam will be produced by 80\over 2 × 22.4 × 8.96 = 16 g

Hence, 16 g of ammonium nitrate is required to be heated.

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