NH4NO3 ⟶ N2O + 2H2O
80 g 1 vol 2 vol
1 vol. of di nitrogen produced at the same time as 8.96 litres of steam (2 vol)
Hence, Vol of di nitrogen = 8.96\over2
= 4.48 lit.
Hence, the volume of di nitrogen oxide produced = 4.48 lit.
(ii) 2 vol = (2 x 22.4) lit steam is produced from 80 g NH4NO3
∴ 8.96 lit of steam will be produced by 80\over 2 × 22.4 × 8.96 = 16 g
Hence, 16 g of ammonium nitrate is required to be heated.