A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Initial velocity (u) = 0 m/s

Final velocity (v) = ?

Height (h) = 19.6 m

g = 9.8 ms⁻²

We know, v² − u² = 2gh

∴ v² − 0² = 2 × 9.8 × 19.6

⇒ v² = 2 × 9.8 × 19.6 = (19.6)²

⇒ v = 19.6 ms⁻¹

Hence, the velocity of the stone just before touching the ground is 19.6 ms⁻¹ .