Question

A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s 2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

August 25, 2024

Answer

Here we have,

Initial velocity (u) = 5 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = – 10 m/s²

Height, i.e. Distance, s =?

Time (t) taken to reach the height =?

We know that, v² = u² + 2as

⇒ 0 = (5)² + 2 × −10 × s

⇒ 0 = 25 − 20s

⇒ s = 25/20 m

⇒ s = 1.25 m

Now, we know that, v = u + at

⇒ 0 = 5 + (–10) × t

⇒ 0 = 5 − 10t

⇒ t = 5/10 s

⇒ t = 0.5 s

Thus, stone will attain a height of 1.25 m and time taken to attain the height is 0.5 s.

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