Here we have,

Initial velocity (u) = 5 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = – 10 m/s^{2}

Height, i.e. Distance, s =?

Time (t) taken to reach the height =?

We know that, v^{2} = u^{2} + 2as

⇒ 0 = (5)^{2} + 2 × −10 × s

⇒ 0 = 25 − 20s

⇒ s = 25/20 m

⇒ s = 1.25 m

Now, we know that, v = u + at

⇒ 0 = 5 + (–10) × t

⇒ 0 = 5 − 10t

⇒ t = 5/10 s

⇒ t = 0.5 s

Thus, stone will attain a height of 1.25 m and time taken to attain the height is 0.5 s.