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Question

A stone of mass 500 g is thrown vertically upwards with a velocity of 15 ms-1.
Calculate:
(a) the potential energy at the greatest height,
(b) the kinetic energy on reaching the ground
(c) the total energy at its half waypoint.

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Answer

Mass (m) = 500 g

Velocity (v) = 15 ms-1

(a) We know,

Potential energy at maximum height = initial kinetic energy

⇒ mgh = 1\over 2mv2

Substituting the values in the equation we get,

KE = 1\over 2 × 0.500 × 152

= 1\over 2 × 0.500 × 225

= 56.25 J

∴ Potential energy at maximum height = Initial kinetic energy = 56.25J

(b) As we know that,

Kinetic energy on reaching the ground = potential energy at the greatest height

= 56.25 J

(c) Total energy at its halfway point = 1\over 2 (K + U)

= 56.25 J

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