Mass (m) = 500 g
Velocity (v) = 15 ms-1
(a) We know,
Potential energy at maximum height = initial kinetic energy
⇒ mgh = 1\over 2mv2
Substituting the values in the equation we get,
KE = 1\over 2 × 0.500 × 152
= 1\over 2 × 0.500 × 225
= 56.25 J
∴ Potential energy at maximum height = Initial kinetic energy = 56.25J
(b) As we know that,
Kinetic energy on reaching the ground = potential energy at the greatest height
= 56.25 J
(c) Total energy at its halfway point = 1\over 2 (K + U)
= 56.25 J