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Question

A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?

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Answer

t = 1.02 s,

v = 1531 m/s

distance, d = v × t

= 1531×1.022 m

= 780.81 m

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