time (t) = 1.02 s,
velocity (v) = 1531 m/s
distance, d = v × t
= 1531×1.022 m
= 780.81 m
Question
A submarine emits a sonar pulse, which returns from an underwater cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff?
WhatsApp
Didn't liked the above answer ?
×
![Crop Image]()
💡 Some Related Questions