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Question

(a) The diameter of neck and bottom of a bottle are 2 cm and 10 cm respectively. The bottle is completely filled with oil. If the cork in the neck is pressed in with a force of 1.2 kgf, what force is exerted on the bottom of the bottle ? (b) Name the law/principle you have used to find the force in part (a)

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Answer

Radius of neck (r1) = 2/2 = 1 cm

Area of neck (A1) = π (1)2 = π cm2

Radius of bottom (r2) = 10/2 = 5 cm

Area of bottom (A2) = π (5)2 = 25π cm2

{F_1\over A_1 } = {F_2\over A_2}

{1.2\over π } = {F_2\over 25π}

⇒ F2 = {1.2\over π }× 25π = 1.2 × 25 = 30 kgf

Hence, force exerted at the bottom of the neck = 30 kgf.

(b) The Pascal’s law is applied to solve the part (a) which states that the pressure exerted anywhere in a confined liquid is transmitted equally and undiminished in all directions throughout the liquid.

Hence,

{F_1\over A_1 } = {F_2\over A_2}

 

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