Initial velocity of the truck, u = 0 m/s
Time taken, t = 20 s
Distance covered by the stone, s = 400 m
According to the second equation of motion:
š = š¢š” + 1/2 šš”2
We have
400 = 0 Ć 20 +1/2 Ć š Ć (20)2
ā 400 = 200š
ā š = 2 š/š 2
Now, Force = mass Ć acceleration
ā š¹ = 7000 Ć 2 = 14000 š