Question

Aluminium carbide reacts with water according to the following equation :
Al4C3 + 12H2O ⟶ 4Al(OH)3 + 3CH4
(i) State what mass of aluminium hydroxide is formed from 12 g. of aluminium carbide.
(ii) State the volume of methane at s.t.p. obtained from 12 g of aluminium carbide.
[relative molecular weight of Al4Cl3] = 144 ; Al(OH)3 = 78

  • Percentage Composition
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Answer

Al4C3 + 12H2O ⟶ 4Al(OH)3 + 3CH4

144 g                       312 g        67.2 lit

144 g of aluminium carbide forms 312 g of aluminium hydroxide.

∴ 12 g of aluminium carbide will form 312\over 144 × 12

= 26 g of aluminium hydroxide

Hence, 26 g of aluminium hydroxide is formed.

(ii) 144 g of aluminium carbide forms 67.2 lit of methane.

∴ 12 g of aluminium carbide will form 67.2\over 144 × 12

= 5.6 lit.

Hence, vol. of methane obtained at s.t.p. = 5.6 lit.

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