Al4C3 + 12H2O ⟶ 4Al(OH)3 + 3CH4
144 g 312 g 67.2 lit
144 g of aluminium carbide forms 312 g of aluminium hydroxide.
∴ 12 g of aluminium carbide will form 312\over 144 × 12
= 26 g of aluminium hydroxide
Hence, 26 g of aluminium hydroxide is formed.
(ii) 144 g of aluminium carbide forms 67.2 lit of methane.
∴ 12 g of aluminium carbide will form 67.2\over 144 × 12
= 5.6 lit.
Hence, vol. of methane obtained at s.t.p. = 5.6 lit.