Question

An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of 1.7 ms-2 ?

  • force and laws of motion CBSE Class 9
WhatsApp

Answer

Mass of the automobile vehicle, m = 1500 kg

Final velocity, v = 0 m/s

Acceleration of the automobile, a = –1.7 ms–2

From Newton’s second law of motion:

Force = Mass × Acceleration = 1500 × (–1.7) = –2550 N

Hence, the force between the automobile and the road is –2550 N, in the direction opposite to the motion of the automobile.

Was this answer helpful?

Didn't liked the above answer ?

Text Generation Tool

💡 Some Related Questions

force and laws of motion

Akhtar, Kiran and Rahul were riding in a motor car that was moving with a high velocity on an expressway when an insect hit the windshield and got stuck on the windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect. And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions.

Open Answer »
force and laws of motion

Mass of one of the objects, m1 = 1.5 kg Mass of the other object, m2 = 1.5 kg Velocity of m1 before collision, v1 = 2.5 m/s Velocity of m2, moving in opposite direction before collision, v2 = -2.5 m/s (Negative sign arises because mass m2 is moving in an opposite direction) After collision, the two objects stick together. Total mass of the combined object = m1 + m2 Velocity of the combined object = v According to the law of conservation of momentum: Total momentum before collision = Total momentum after collision m1v1 + m2 v2 = (m1 + m2) v 1.5(2.5) + 1.5 (-2.5) = (1.5 + 1.5) v 3.75 – 3.75 = 3 v v = 0 Hence, the velocity of the combined object after collision is 0 m/s.

Open Answer »