(i) The dipole moment |P| = q × 2a
Force on -q at A = -qE
Force on +q at B = +qE
Net force on the dipole = qE – qE = 0
(ii) We know that work done in rotating an electric dipole from θ1 to θ2, (where θ 1 is the angle of the dipole with electric field) is given by,
W = pE (cos θ1 − cos θ2) now given θ1 = 0º, θ2 = 180º
∴ W = pE(cos 0 − cos 180) = 2pE
![An electric dipole is held in a uniform electric field. (i) Show that the net force acting on it is zero. (ii) The dipole is aligned parallel to the field. Find the work done by rotating it through the angle of 180°. [CBSE (AI) 2012] 2 Show that the net force acting on it is zero](/wp-content/uploads/2024/01/7-25-1.png)