1. Boojho is at rest, i.e., his speed is zero because the graph is constant between point B and C.
2. Non-uniform.
3. Speed = 225-150\over 12-8 = 75\over 4 =18.75 m/min
Question
Boojho goes to the football ground to play football. The distance-time graph of his journey from his home to the ground is given in figure.
Q1. What does the graph between point B and C indicate about the motion of Boojho? Q2. Is the motion between 0 to 4 minutes uniform or non-uniform? Q3. What is his speed between 8 and 12 minutes of his journey?
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💡 Some Related Questions
Distance between Bholu’s and Golu’s house is 9 km. Bholu has to attend Golu’s birthday party at 7 o’clock. He started from his home at 6 o’clock on his bicycle and covered a distance of 6 km in 40 minutes. At that point he met Chintu and he spoke to him for 5 minutes and reached Golu’s birthday party at 7 o’clock. With what speed did he cover the second part of the journey? Calculate his average speed for the entire journey.
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Q1. What will be the position of the object at 20 s? Q2. What will be the distance travelled by the object in 12 s? Q3. What is the average speed of the object? 
Complete the data of the table given below with the help of the distance-time graph given in figure.
| Distance (m) | 0 | 4 | ? | 12 | ? | 20 |
| Time (s) | 0 | 2 | 4 | ? | 8 | 10 |