Question

Calculate the number of electrons present in 15.4 of carbon tetrachloride CCl4

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Answer

Number of moles of CCl4 Mass\ of\ CCl_4 / Molecular\ mass\ of\ CCl_4

= 15.4 \over 154

∵ = 0.1 mole

1 mole of CCl4 = 6.022 × 1023 molecules of CCl4

∴ 0.1 mole of CCl4= 0.1 × 6.022 × 1023 moles of CCl4

= 6.022 × 1022 molecules of CCl4

We know that one atom of carbon has 6 electrons and one atom of chlorine has 17 electrons.

Therefore, one molecule of CCl4 will contain 6 + (4 × 17) = 74 electrons.

∴ Number of electrons in 6.022 × 1022 molecules of CCl4

= 74 × 6.022 × 1022 electrons

= 445.6 × 1022 electrons

= 4.456 × 1024 electrons

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