In photosynthesis, 6 molecules of carbon dioxide combine with an equal number of water molecules through a complex series of reactions to give a molecule of glucose having a molecular formula C6H12O6. How many grams of water would be required to produce 18 g of glucose? Compute the volume of water so consumed assuming the density of water to be 1g cm-3.



6CO2 + 6 H2O →Chlorophyll + Sunlight →  C6H12O6 + 6O2

1 mole of glucose needs 6 moles of water

180 g of glucose needs (6 × 1 8) g of water

1 g of glucose will need 108 / 180 g of water.

18 g of glucose would need (108 / 180 × 18) g of water = 10.8 g

Volume of water used = Mass / Density

= 10.8 g / 1 g cm−3

= 10.8 cm3

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