Question

Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.

August 1, 2024

Answer

2KClO₃ ⟶ 2KCl + 3O₂

O₂ : KClO₃

3 : 2

6 : x

x = $2\over 3$ × 6

⇒ x = 4 moles

Hence, 4 moles of KClO₃ are required to give 6 moles of oxygen.

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