Question

Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.

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Answer

2KClO3 ⟶ 2KCl + 3O2

O2    :   KClO3

3       :    2

6       :    x

x = 2\over 3  × 6

⇒ x = 4 moles

Hence, 4 moles of KClO3 are required to give 6 moles of oxygen.

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