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Question

Calculate the percentage of sodium in sodium aluminium fluoride (Na3AlF6) correct to the nearest whole number. [F = 19 ; Na = 23 ; Al = 27]

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Answer

Molecular weight of sodium aluminium fluoride (Na3AlF6)

= 3(23) + 27 + 6(19)

= 69 + 27 + 114

= 210 g

210 g of sodium aluminium fluoride contains 69 g of Na

∴ 100 g of sodium aluminium fluoride will contain

= 69\over 210 × 100

= 32.85% = 33%

Hence, percentage of sodium in sodium aluminium fluoride (Na3AlF6) is 33%

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