Weight of 112 lit of CH3OH = 160 g [at s.t.p.]
∴ Weight of 1 lit of CH3OH = 160\over 112
= 1.4286 g
Weight of 1 lit of H2 = 0.09 g [at s.t.p.]
Under similar temperature and pressure,
Vapour density of gas methyl alcohol
= 1.4286\over 0.09
= 15.87 ≈ 16
Molecular weight = 2 × Vapour density
= 2 × 15.87 = 31.74 g ≈ 32 g
Hence, molecular weight of methyl alcohol is 32 g and vapour density of methyl alcohol is 16