Question

Calculate the volume occupied by 3.5 g of O2 gas at 27 °C and 740 mm pressure. [O = 16]

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Answer

Gram molecular mass of O2 = 2 × 16 = 32 g

1 mole of O2 weighs 32 g and occupies 22.4 lit. vol.

∴ 3.5 g of O2 occupies = = 22.4\over 32 × 3.5

Volume occupied by 3.5 g of O2 gas at 27°C and 740 mm pressure:

s.t.p. given values
P1 = 760 mm of Hg P2 = 740 mm of Hg
V1 = 2.45 lit V2 = x lit
T1 = 273 K T2 = 27 + 273 K

Using the gas equation,

P_1V_1\over T_1=P_2V_2\over T_2

Substituting the values we get,

760 × 2.45\over 273=740× x\over 300

⇒ x = 760 × 2.45 × 300\over 740 × 273

x = 2.76 lit

Hence, the volume occupied by 3.5 g of O2 gas at 27°C and 740 mm pressure is 2.76 lit.

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