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Question

Calculate the volume of 320 g of SO2 at stp. [S = 32 and O = 16]

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Answer

gram molecular mass of SO2 = 32 + 2(16)

= 32 + 32 = 64 g

64 g of SO2 occupy 22.4 lit of vol.

320 g of SO2 will occupy = 22.4\over64 × 320 = 112 lit

Hence, volume of 320 g of SO2 = 112 lit.

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