C3H8 + 5O2 → 3CO2 + 4H2O
44 g 22.4 lit
(i) 44 g propane requires 5 x 22.4 lit of oxygen
∴ 8.8 g of propane will require 5 × 22.4\over44 x 8.8 = 22.4 lit.
Hence, 22.4 lit of Oxygen is required.
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