C3H8 + 5O2 → 3CO2 + 4H2O
44 g 22.4 lit
(i) 44 g propane requires 5 x 22.4 lit of oxygen
∴ 8.8 g of propane will require 5 × 22.4\over44 x 8.8 = 22.4 lit.
Hence, 22.4 lit of Oxygen is required.
Question
Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane [C3H8]. [C = 12, O = 16, H = 1, Molar Volume = 22.4 dm3 at s.t.p.]
WhatsApp
Didn't liked the above answer ?
×
![Crop Image]()
💡 Some Related Questions
Aluminium carbide reacts with water according to the following equation : Al4C3 + 12H2O ⟶ 4Al(OH)3 + 3CH4 (i) State what mass of aluminium hydroxide is formed from 12 g. of aluminium carbide. (ii) State the volume of methane at s.t.p. obtained from 12 g of aluminium carbide. [relative molecular weight of Al4Cl3] = 144 ; Al(OH)3 = 78
Open Answer »From the equation : (NH₄)₂Cr₂O₇ ⟶ N₂(g) + 4H₂O(g) + Cr₂O₃ Calculate: (i) the quantity in moles of (NH₄)₂Cr₂O₇ if 63 gm of (NH₄)₂Cr₂O₇ is heated. (ii) the quantity in moles of N₂ formed. (iii) the volume in litres or dm3 of N₂ evolved at s.t.p. (iv) the mass in grams of Cr₂O₃ formed at the same time. [H = 1, Cr = 52, N = 14]
Open Answer »Commercial NaOH weighing 30 g. has some NaCl in it. The mixture on dissolving in water and treatment with excess AgNO3 soln. formed a precipitate weighing 14.3 g. What is the percentage of NaCl in the commercial sample of NaOH. NaCl + AgNO3 ⟶ AgCl + NaNO3 [Relative molecular mass of NaCl = 58 ; AgCl = 143]
Open Answer »A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at step.) NH4NO3 ⟶ N2O + 2H2O (i) What volume of di nitrogen oxide is produced at the same time as 8.96 litres of steam. (ii) What mass of ammonium nitrate should be heated to produce 8.96 litres of steam [Relative molecular mass of NH4NO3 is 80]
Open Answer »