NaCl + AgNO3 ⟶ AgCl + NaNO3
58 g 143 g
(i) 143 g AgCl is formed by 58 g NaCl
∴ 14.3 g of AgCl will be formed by 58\over143[/katek] × 14.3 = 5.8 g
Percentage of NaCl = 5.8\over30[/katek] × 100
= 19.33%
Hence, percentage of NaCl is 19.33%
NaCl + AgNO3 ⟶ AgCl + NaNO3
58 g 143 g
(i) 143 g AgCl is formed by 58 g NaCl
∴ 14.3 g of AgCl will be formed by 58\over143[/katek] × 14.3 = 5.8 g
Percentage of NaCl = 5.8\over30[/katek] × 100
= 19.33%
Hence, percentage of NaCl is 19.33%
Was this answer helpful?