Question

Derive expression for force of attraction between two bodies and then define gravitational constant.

WhatsApp

Answer

“Everybody in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by

F ∝ m1 × m2          … (1)

and      F ∝ {1 \over 𝑟^2}    … (2)

Combining (1) and (2), we get

F ∝ {𝑚_1×𝑚_2 \over 𝑟^2}

Or      F = G × {𝑚_1𝑚_2 \over 𝑟^2}  … (3)

where G is a constant known as universal gravitational constant.

Here, if the masses m1 and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1m in the above formula, we get

G = F

Thus, the gravitational constant G is numerically equal to the force of gravitation which exists between two bodies of unit masses kept at a unit distance from each other.

Was this answer helpful?

Didn't liked the above answer ?

Text Generation Tool

💡 Some Related Questions

Velocity-time graph for the ball’s motion is shown in figure.

Observe the graph and answer the following questions. Assume that g = 10 m/s2 and that there is no air resistance. (a) In which direction is the ball moving at point C? (b) At which point is the ball stationary? (c) At which point is the ball at its maximum height? (d) what is the ball’s acceleration at point C? (e) What is the ball’s acceleration at point A? (f) What is the ball’s acceleration at point B? (g) At which point does the ball have the same speed as when it was thrown?

Open Answer »