Question

Figure shows a uniform metre rule placed on a fulcrum at its mid-point O and having a weight 40gf at the 10 cm mark and a weight of 20 gf at the 90 cm mark.
(i) Is the metre rule in equilibrium? If not, how will the rule turn?
(ii) How can the rule be brought in equilibrium by using an additional weight of 40gf?
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Answer

(a) Anticlockwise moment = F × r

= 40 gf × (50 – 10) cm

= 40 × 40

= 1600 gf cm

Clockwise moment = F × r

= 20 gf × (90 – 50) cm

= 20 × 40

= 800 gf cm

So, the meter rule will not be in equilibrium. It will turn in anticlockwise direction.

(ii) To balance the rule in equilibrium 40gf should be kept on right side.

Let distance from middle = d cm

So clockwise moment becomes

Extra moment = 1600 gf cm – 800 gf cm

= 800 gf cm

Now, 40 × d = 800

⇒ d = 800\over 40 = 20 cm

So, the additional weight should be placed at 70cm mark to bring the rule in equilibrium.

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