Question

Figure shows two forces each of magnitude 10N acting at the points A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of the two forces about the point (i) A, (ii) B and (iii) O, situated exactly at the middle of the two forces.

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Answer

Force at A = 10 N

Force at B = 10 N

Distance between A and B = 50 cm = 0.5 m

(i) Resultant moment of two forces at point A is

= 10 × 0.5 = 5 N m clockwise

Therefore, resultant moment of two forces at point A is 5 Nm (clockwise)

(ii) Resultant moment of two forces at point B is

= 10 × 0.5 = 5 N m clockwise

Therefore, resultant moment of two forces at point B is 5 Nm (clockwise)

(iii) Perpendicular distance of point O from either of the forces F = 10N is 0.25 m

Moment of force F at point A about O

= 10 × 0.25 = 2.5 N m clockwise

Moment of force F at point B about O

= 10 × 0.25 = 2.5 N m clockwise

Resultant moment of two forces about O

= 2.5 + 2.5 = 5 N m

Therefore, Resultant moment of two forces about o is 5Nm (clockwise)

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