Force at A = 10 N
Force at B = 10 N
Distance between A and B = 50 cm = 0.5 m
(i) Resultant moment of two forces at point A is
= 10 × 0.5 = 5 N m clockwise
Therefore, resultant moment of two forces at point A is 5 Nm (clockwise)
(ii) Resultant moment of two forces at point B is
= 10 × 0.5 = 5 N m clockwise
Therefore, resultant moment of two forces at point B is 5 Nm (clockwise)
(iii) Perpendicular distance of point O from either of the forces F = 10N is 0.25 m
Moment of force F at point A about O
= 10 × 0.25 = 2.5 N m clockwise
Moment of force F at point B about O
= 10 × 0.25 = 2.5 N m clockwise
Resultant moment of two forces about O
= 2.5 + 2.5 = 5 N m
Therefore, Resultant moment of two forces about o is 5Nm (clockwise)