Find the length of a seconds’ pendulum at a place where g = 10 ms-2 (Take π = 3.14).

As we know,

T = 2 \pi \sqrt{l\over g}

Given,

g = 10 ms^-2

π = 3.14

T = 2 s

Substituting the values in the formula above we get,

2 = 2 × 2 × 3.14 2 \pi \sqrt{l\over 10}

⇒ ({2\over 2 \times 3.14}) = \sqrt{l\over g}

⇒ ({2\over2 \times 3.14})^2 = l\over 10

⇒ (0.318)² = l\over 10

⇒ 0.10142 = l\over 10

⇒ l = 1.0142

Hence, length of a seconds’ pendulum = 1.0142 m