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Question

Four g of a metallic chloride contains 1.89 g of the metal ‘X’. Calculate the empirical formula of the metallic chloride. [At. wt. of ‘X’ = 64, Cl = 35.5]

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Answer

4 g of metallic chloride contains 1.89 g of metal X

∴ 100 g of metallic chloride contains 1.89\over4 × 100 = 47.25 g of metal X

∴ % of Cl in the metallic chloride = 100 – 47.25 = 52.75%.

Element % composition At. wt. Relative no. of atoms Simplest ratio
X 47.25 64 47.25/64 = 0.738 0.738/0.738 = 1
Cl 52.75 35.5 52.75/35 = 1.48 1.48/0.738 = 2

X : Cl = 1 : 2

Hence, empirical formula is XCl2

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