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Question

From the equation : C + 2H2SO4 ⟶ CO2 + 2H2O + 2SO2
Calculate :
(i) The mass of carbon oxidized by 49 g of sulphuric acid [C = 12 ; relative molecular mass of H2SO4 = 98].
(ii) The volume of SO2 measured at s.t.p., liberated at the same time.

Percentage Composition

Chemistry, Class 10, ICSE, J Dalal

August 6, 2024

Answer

C + 2H₂SO₄ ⟶ CO₂ + 2H₂O + 2SO₂

12 g 196 g

(i) 196 g of sulphuric acid oxidizes 12 g carbon

∴ 49 g of sulphuric acid will oxidize = 12\over196[/katek] × 49

= 3 g

Hence, 3 g of carbon is oxidized.

(ii) 12 g carbon liberates 2 vol = (2 x 22.4) lit of SO₂

∴ 3 g of carbon will liberate 2 × 22.4\over12[/katek] × 3

= 11.2 lit of SO₂.

Hence, 11.2 lit of SO₂ is liberated.

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