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Question

From the equation : (NH4)2 Cr2O7 ⟶ Cr2O3 + 4H2O + N2 Calculate :
(i) the vol. of nitrogen at STP, evolved when 63 g. of ammonium dichromate is heated.
(ii) the mass of Cr2O3 formed at the same time.
[N = 14, H = 1, Cr = 52, O = 16]

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Answer

(NH4)2Cr2O7 {\overset{ \triangle }{\longrightarrow}} Cr2O3 + 4H2O + N2

252 g                    152 g              22.4 lit

252 g of ammonium dichromate gives 22.4 lit of nitrogen

∴ 63 g of ammonium dichromate will give = 22.4\over252 × 63

= 5.6 lit of nitrogen.

Hence, 5.6 lit of nitrogen is evolved.

(ii) 252 g of ammonium dichromate gives 152 g Cr2O3

∴ 63 g of ammonium dichromate will give = 152\over252 × 63

= 38 g

Hence, 38 g of Cr2O3 is formed.

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