(NH4)2Cr2O7 {\overset{ \triangle }{\longrightarrow}} Cr2O3 + 4H2O + N2
252 g 152 g 22.4 lit
252 g of ammonium dichromate gives 22.4 lit of nitrogen
∴ 63 g of ammonium dichromate will give = 22.4\over252 × 63
= 5.6 lit of nitrogen.
Hence, 5.6 lit of nitrogen is evolved.
(ii) 252 g of ammonium dichromate gives 152 g Cr2O3
∴ 63 g of ammonium dichromate will give = 152\over252 × 63
= 38 g
Hence, 38 g of Cr2O3 is formed.