From the given displacement-time graph, answer the following questions:

(i) The kind of motion depicted in this graph is :

- uniform
- non-uniform
- retardation
- all of the above

(ii) The velocity between points A and C is:

- 20 ms
^{-1} - 5 ms
^{-1} - 10 ms
^{-1} - 15 ms
^{-1}

(iii) The displacement at t = 3s is:

- 15 m/s
^{2} - 12.5 m/s
^{2} - 40 m
- 30 m

(i) uniform

**Reason** — As the graph shows the linear relationship between displacement and time i.e., the car travels an equal distance in equal intervals of time in a certain direction. Thus, it is moving with **uniform** motion.

(ii) 10 ms^{-1}

**Reason** — As, velocity is the ratio of displacement and time, therefore,

Velocity = Slope of straight line AC

= 60-30\over 5-2

= 30\over 3

= 10 m s^{-1}

(iii) 40 m

**Reason** — When we observe the graph, we notice that at t = 3 s, the displacement axis shows 40 m, hence, displacement at t = 3 s is **40 m**