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Question

Group numbers1 – IA2 – IIA13 – IIIA14 – IVA15 – VA16 – VIA17 – VIIA18 – 0
2nd periodLiDOJNe
3rd periodAMgESiHM
4th periodRTIQuy
</br>In the above table, H does not represent hydrogen. </br>Some elements are in their own symbol and position in the periodic table, while others are shown with a letter. </br>Identify : </br>(i) The most electronegative element. </br>(ii) The most reactive element of group I. </br>(iii) The element from period 3 with least atomic size. </br>(iv) The noble gas of the fourth period. </br>(v) How many valence electrons are present in Q. </br>(vi) Which element from group 2 would have the least ionization energy? </br>(vii) In the compound between A and H, what type of bond is formed and give it’s molecular formula.

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Answer

(i) J is the most electronegative element.

(ii) R is the most reactive element of group 1.

(iii) M is the element from period 3 with least atomic size.

(iv) y is the noble gas of the fourth period.

(v) 5 valence electrons present in Q.

(vi) T is the element from group 2 which has least ionization energy.

(vii) ionic bond is formed between A and H.

The molecular formula is :

2A + H ⟶ A2H

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In period 2, element ‘A’ is to the right of element ‘B’
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