(a) Given,
Length of the iron rail = 3.3 km
Converting km to m, we get,
1 km = 1000 m
Therefore, 3.3 km = 1000 x 3.3 = 3300 m
Speed of the sound in iron (V) = 5280 m s-1
t = ?
5280 = 3300\over Time (t)
⇒ t = 3300\over 5280
⇒ t = 0.625 s
Therefore, the time taken by sound to travel in iron rail = 0.625 s
(b) Speed of sound in air = 330 m s-1
Substituting the values in the above formula, we get,
330 = 3300\over Time (t)
⇒ t = 3300\over 330 = 10 s
Therefore, the time taken by sound to travel in air = 10 s