H2 | + | Cl2 | → | 2HCl |
1 vol | : | 1 vol | 2 vol |
To calculate the amount of hydrogen used
Cl2 | : | H2 |
1 | : | 1 |
4 | : | x |
⇒ x = 1\over 1 × 4 = 4 lit
Remaining hydrogen = 6 – 4 = 2 lit.
To calculate the amount of HCl :
Cl2 | : | HCl |
1 | : | 2 |
4 | : | x |
⇒ x = 2\over 1 × 4 = 8 lit
Hence, after reaction 8 lit of HCl is formed which dissolves in water and 2 lit of hydrogen is left.
∴ 2 lits. of hydrogen is left.