Question

If the length, breadth and height of one packet of one gross match box are 2.8 lcm and 0.9 dcm respectively, then let us calculate the volume of one match box [one gross = 12 dozen]. But if the length and breadth of one match box be 5 cm and 3.5 cm, then let us calculate the height of it.

January 1, 2024

Answer

Volume of 1 gross (12 × 12) match boxes = (2.8 × 1.5 × 0.9) cu. dcm.

Volume of 1 match box $=\frac{2.8 × 1.5 × 0.9}{12 × 12}$ cu.dcm.

$=\frac{3.780}{12 × 12} \text { cu.dcm }$ = 0.02625 cu.dcm

= 26.25 cu.cm.

Let the height of a match box = h cm.

∴ Volume = 5 × 3.5 × h cu.cm.

∴ 17.5 h = 26.25

∴ h $=\frac{26.25}{17.5}$ =1.5 cm .

∴ Height of each match box = 1.5 cm.

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