Diagonal of a cube = 4 \sqrt{3}cm.
As diagonal of a cube =\sqrt{3} × side.
Length of one side of the cube =\frac{4 \sqrt{3}}{\sqrt{3}}=4 cm
\therefore Total surface area of a cube = 6 × (side)2
= 6 × (4)2 = 16 × 6 sq cm
= 96 sq cm
∴ 96 sq cm
Diagonal of a cube = 4 \sqrt{3}cm.
As diagonal of a cube =\sqrt{3} × side.
Length of one side of the cube =\frac{4 \sqrt{3}}{\sqrt{3}}=4 cm
\therefore Total surface area of a cube = 6 × (side)2
= 6 × (4)2 = 16 × 6 sq cm
= 96 sq cm
∴ 96 sq cm