Consider the following displacement reaction in which Fe displaces Cu from CuSO4 to form FeSO4:
{𝐹𝑒(𝑠) \over 𝐼𝑟𝑜𝑛} + {𝐶𝑢𝑆𝑂_4(𝑎𝑞) \over\ copper\ sulphate\ (𝐵𝑙𝑢𝑒)} → {𝐹𝑒𝑆O_4(aq) \over Iron\ (II) sulphate\ (𝐺𝑟𝑒𝑒𝑛)} + {𝐶𝑢(𝑠) \over 𝐶𝑜𝑝𝑝𝑒𝑟\ (𝑅𝑒𝑑𝑑𝑖𝑠ℎ−𝑏𝑟𝑜𝑤𝑛)}In the above reaction, Fe is gaining oxygen. Hence, Fe is oxidised. CuSO4 is loosing oxygen. Hence, it is reduced. So, it is a redox reaction.