Question
The volume of 4.4 g of CO2 at STP is –
- 22.4 L
- 2.24 L
- 224 L
- 44.8 L
Answer
(b) 2.24 L
Explanation:
Molar mass of CO2 = 12 + 16 × 2 = 44 g
Number of moles (n) = 4.4/44 = 0.1
Temperature (T) = 273 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 L.atm/mol.K
PV = nRT
(1 atm) × V = (0.1 moles) × (0.0821 L.atm/mol.K) × (273 K)
V = 0.1 × 0.0821 × 273 /1 = 2.24 L