Question

Name the following : (i) A metallic ore converted to it’s oxide – iron [II] oxide on heating the concentrated ore.
(ii) A black metallic oxide reduced to metal on heating with coke.  
(iii) The compound which on ignition at elevated temperatures gives pure alumina.  
(iv) The non-metal which forms the anode during electrolytic reduction of fused alumina in Hall Heroult’s process.  
(v) A metal other than manganese, present in duralumin but not in magnalium.

  • Metallurgy
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Answer

(i) Spathic Iron Ore (Iron [II] Carbonate, FeCO3)

(ii) CuO

(iii) Aluminium hydroxide

(iv) Carbon (Graphite)

(v) Copper (Cu)

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Metallurgy

Give reasons for the following pertaining to Hall Herault’s process.
(i) The fusion temperature of the electrolyte has to be lowered before conducting the electrolytic reduction.
(ii) The constituents of the electrolyte in addition to one part of fused alumina contains three parts of cryolite and one part of fluorspar.
(iii) A layer of powdered coke sprinkled over the electrolytic mixture, protects the carbon electrodes.
(iv) It is preferred to use a number of graphite electrodes as anode, instead of a single graphite electrode.

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