P + 5HNO3 → H3PO4 + H2O + 5NO2
31 g 98 g
(i) 31 g of P = 1 mole
∴ 9.3 g of P = 1\over 31 × 9.3 = 0.3 moles.
Hence, 0.3 moles of phosphorous was taken for the reaction.
(ii) 31 g of P forms 98 g of phosphoric acid
∴ 9.3 g will form 98\over 31 × 9.3 = 29.4 g.
Hence, 29.4 g. of phosphoric acid is formed
(iii) 31 g of P produces 5 vol = 5 x 22.4 lit.
∴ 9.3 g will produce =5 × 22.4\over 31 × 9.3
= 33.6 lit.