F = {1\over 4 \pi\varepsilon_0}{q_1q_2\over r^2}
The graph between F and 1/r² is a straight line of slope {1\over 4 \pi\varepsilon_0}{q_1q_2}[/katex] passing through the origin in both cases.
Since, magnitude of the slope is more for attraction, therefore, attractive force is greater than repulsive force.
![Plot a graph showing the variation of coulomb force (F) versus 1/r², where r is the distance between the two charges of each pair of charges: (1 µC, 2 µC) and (2 µC, – 3 µC). Interpret the graphs obtained. [CBSE (AI) 2011] 2 2 6 1](/wp-content/uploads/2024/01/2-6-1.png)